

\subsection{\bf Proof of Maximum Likelihood}
\subsection{\bf Part (b): Formula for Error---III}

\begin{slide}
\begin{itemize}
\item So $\sigma^2_{\rm statistical\/}$ is just $\frac{1}{n\langle
g\rangle}$ which is exactly equal to $\langle \sigma^2_{\rm physics}
\rangle$ from Equation~(18).

\item The difference between $\sigma^2_{\rm physis}$ and $\langle
\sigma^2_{\rm physics} \rangle$ is no sweat:

\item Thus, from central limit theorem $\langle \sigma^2_{\rm physics}
\rangle$ and $\sigma^2_{\rm physics}$ differ only by relative error
$O\left( \frac{1}{\sqrt{n}} \right)$ which tends to 0 as
$n\rightarrow\infty$.

\item One can normally ignore such ``errors'' in the error estimate.
\end{itemize}
\end{slide}

