Basic HTML version of Foils prepared 2 September 1997

Foil 27 What does the Laplace Update calculation look like?

From CPS615 Laplace Example -- Programming Models and Performance CPS615 Basic Simulation Track for Computational Science -- Fall Semester 97. by Geoffrey C. Fox
1 In the sequential code, a single processor updates in turn (16x16=256-60=196) internal points. Each update is j --> 0.25 *(j up + jdown + jleft + jright ) involves 4 floating point operations for each point
2 In the parallel case, each processor updates in turn the points for which it is responsible - this is "owner computes rule"
3 A corner processor updates nine points
4 (the small internal points)
5 A "general" central processor
6 updates sixteen points
in Table To:

© on Tue Oct 7 1997